BUAA-SUMMER-PYTHON 第一次课上作业
前言
这是2024-BUAA-Python 课程的一些经验分享。
该网页含有课上和课下题目,没有题解。如要看题解(笨笨我写的,不是很好),可以移步https://github.com/Afeii1/BUAA_Summer_Python
选择题
Which option is the result of 100//3?
A. 33
B. 34
C. 33.333333333333333
D. 0.333333333333333x is a two-digit integer variable. Which statement swaps its tens and units digits?
A (x%10)10+x%10
B (x%10)10+x//10
C (x/10)%10+x%10
D (x/10)%10+x//10The output of the following code is ();
a,b,c,d,e,f = 'Python'
b =A.1
B.0
C.Error
D.’y’Which of the following statements is illegal in Python ()?
A. x = y = z = 1
B. x = (y = z + 1)
C. x, y = y, x
D. x += yWhich of the following statements about Python’s floating-point type is wrong ?
A. There are two ways to represent floating-point numbers: decimal notation and scientific notation
B. The floating-point type is consistent with the concept of real numbers in mathematics, representing values with decimals
C. sys.float_info can list in detail the floating-point parameters of the system where the Python interpreter runs
D. Floating-point numbers in the Python language can be without decimals
填空题
The result of the Python statement ‘’.join(list(‘hello BUAA!’)) is__!
In Python, modules can be imported using the keyword _ .
In Python, statement blocks are divided by _. (indentation/brace/line breaks)
The output of excuting the code blow is __
tmp = ‘ab’ + ‘c’*2
print(tmp)- Consider the following code snippet:
x = [1, 2, 3, 4]
y = [num * 2 for num in x]
The value of y after execution is _ .
编程题
- 平方和
【Description】
The user inputs a positive integer n . Calculate the sum of squares from 1 to n (1^2 + 2^2 + ….+ n^2).
【Input】
A line contains an integer n.
【Output】
The result of the sum of squares from 1 to n
【Examples Input】
3
【Examples output】
14
【Example description】
1^2 + 2^2 + 3^2 = 14
【Notes】
For 100% of test cases, a,b in [1, 10000]. Calculate GPA
【Problem Description】
Li Hua is a student of Beihang University. Can you help him calculate his GPA this semester using Python?To calculate GPA, you need to use the following method:
First, ignore all courses with less than 1 credit (not including 1).
Then, calculate the grade point for each course: Assume x is the original score of the course,
$GP = \begin{cases}
4 - 3 \cdot \frac{(100-x)^2}{1600} & \text{if } x \geq 60 \
\newline
0 & \text{if } 0 \leq x < 60
\end{cases}$
Next, you need to know how many credits were given for each courses.
After calculating all the steps above, you need to calculate $ GPA = \frac {\sum(GP_i * Gredit_i)}{\sum Gredit_i} $, where credit and GP is given above.
【Input】
First line, an integer N, tells how many courses Li Hua has taken this semester.
Then followed by two lines, each line 2 numbers (integer or float) X C separated by space. The first integer X is the original score of the course, and the second num C is the credit for the course.
【Output】
A floating point rounded to 2 decimals, which is the GPA.
【Sample Input】
4
100 1
60 1
0 1
90 0.2
【Sample Output】
1.67
【Sample Description】
The first course has a GP of 4.0, the second course has a GP of 1.0, and the third course has a GP of 0. The fourth course does not count at all.
GPA=(4.0+1.0+0)/(1+1+1)=1.67
【Data】
1<=N<=1000, N is integer.
0<=X<=100, X is integer.
0<=C<=6, C is float or integer.
All data satisfy that there is at least one class has more than 1 credit.



